2x^2+14x+7=2x-7

Solution for 2x^2+14x+7=2x-7 equation:

2x^2+14x+7=2x-7

We move all terms to the left:

2x^2+14x+7-(2x-7)=0

We get rid of parentheses

2x^2+14x-2x+7+7=0

We add all the numbers together, and all the variables

2x^2+12x+14=0

a = 2; b = 12; c = +14;
Δ = b2-4ac
Δ = 122-4·2·14
Δ = 32
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{32}=\sqrt{16*2}=\sqrt{16}*\sqrt{2}=4\sqrt{2}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(12)-4\sqrt{2}}{2*2}=\frac{-12-4\sqrt{2}}{4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(12)+4\sqrt{2}}{2*2}=\frac{-12+4\sqrt{2}}{4}
$